A charge of $10 \,\mu C$ is placed at the origin of $x-y$ coordinate system. The potential difference between two points $(0, a)$ and $(a, 0)$ in volt will be
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(d)
$V_A=\frac{k q}{a}$
$V_B=\frac{k q}{a}$
$\Delta V=V_A-V_B=0$
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