A charge particle of charge $q$ and mass $m$ is accelerated through a potential diff. $V\, volts$. It enters a region of orthogonal magnetic field $B$. Then radius of its circular path will be
  • A$\sqrt {\frac{{Vm}}{{2q{B^2}}}} $
  • B${\frac{{2Vm}}{{q{B^2}}}}$
  • C$\sqrt {\frac{{2Vm}}{q}} \left( {\frac{1}{B}} \right)$
  • D$\sqrt {\frac{{Vm}}{q}} \left( {\frac{1}{B}} \right)$
Medium
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