A child weighing $25 \,kg$ slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is $200 \,N$, the acceleration of child is ........... $m / s^2$ $\left(g=10 \,m / s ^2\right)$
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(d)
$m g-f_s=m a$
$250-200=25 a$
$a=2 \,m / s ^2$
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