The dumbell is placed on a frictionless horizontal table. Sphere A is attached to a frictionless pivot so that B can be made to rotate

Q: The dumbell is placed on a frictionless horizontal table. Sphere $A$ is attached to a frictionless pivot so that $B$ can be made to rotate about $A$ with constant angular velocity. If $B$ makes one revolution in period $P$, the tension in the rod is

b $T_0=m R w_0^2$ $l^{\prime}=2 l$ $w^{\prime}=2 w^0$ $T^{\prime}=2 m l \times 4 w_0^2$ $T^{\prime}=8 T_0$ $T_0=\frac{\pi^2 Md }{p^2}$ $\therefore T^{\prime}=\frac{8 \pi^2 Md }{ p ^2}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The dumbell is placed on a frictionless horizontal table. Sphere $A$ is attached to a frictionless pivot so that $B$ can be made to rotate about $A$ with constant angular velocity. If $B$ makes one revolution in period $P$, the tension in the rod is

A$\frac{{4{\pi ^2}Md}}{{{P^2}}}$
B$\frac{{8{\pi ^2}Md}}{{{P^2}}}$
C$\frac{{4{\pi ^2}Md}}{P}$
D$\frac{{2Md}}{P}$

Diffcult

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

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