MCQ
$A$ closed planar wire loop of area $A$ and arbitrary shape is placed in a uniform magnetic field of magnitude $B$, with its plane perpendicular to magnetic field. The resistance of the wire loop is $R$. The loop is now turned upside down by $180^o$ so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowed through the wire ring in the process is
  • A
    $< AB/R$
  • B
    $= AB/R$
  • $= 2AB/R$
  • D
    None

Answer

Correct option: C.
$= 2AB/R$
c
induced emf $=\frac{d(f l u x)}{d t}=R \frac{d q}{d t}$

$\Rightarrow \Delta q=\frac{\Delta(f l u x)}{R}=\frac{2 B A}{R}$

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