MCQ
A compound contains $69.5\%$ oxygen and $30.5\%$ nitrogen and its molecular weight is $92$ . The formula of that compound is
  • A
    $N_2O$
  • B
    $NO_2$
  • $N_2O_4$
  • D
    $N_2O_5$

Answer

Correct option: C.
$N_2O_4$
c
moles of oxygen $=69.5 / 16$

$=4.34$

moles of nitrogen $=30.5 / 14$

$=2.18$

ratio of moles of nitrogen and oxygen $=2.18: 4.34$

$=1: 2$

empirical formula $ = NO_2$

molecular formula $=(\mathrm{NO}_ 2) \mathrm{n}$

where $\mathrm{n}=$ molecular mass/ empirical mass

$=92 / 46$

$=2$

therefore the formula of the compound is $\mathrm{N}_ 2 \mathrm{O} _4 .$

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