When 35 , mL of 0.15 , M lead nitrate solution is mixed with 20 ,… - Vidyadip

MCQ

When $35\, mL$ of $0.15\, M$ lead nitrate solution is mixed with $20 \,mL$ of $0.12\, M$ chromic sulphate solution, ....... $\times 10^{-5}$ moles of lead sulphate precipitate out. (Round off to the Nearest Integer).

A
$565$
✓
$525$
C
$235$
D
$412$

✓

Answer

Correct option: B.

$525$

b
$3 Pb \left( NO _{3}\right)_{2}+ Cr _{2}\left( SO _{4}\right)_{3} \rightarrow 3 PbSO _{4}+2 Cr \left( NO _{3}\right)_{3}$

$35\, ml \quad 20\, ml$

$0.15\, M \quad 0.12\, M$

$5.25\, m \cdot mol =2.4\, m \cdot mol \quad 5.25 \,m \cdot mol$

$=5.25 \times 10^{-3} \,mol$

therefore moles of $PbSO _{4}$ formed $=5.25 \times 10^{-3}$ $=525 \times 10^{-5}$

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