MCQ
A compound contains $69.5\%$ oxygen and $30.5\%$ nitrogen and its molecular weight is $92.$ The molecular formula of the compound is
- A$N_2O$
- B$NO_2$
- ✓$N_2O_4$
- D$N_2O_5$
| Element | $\%$ | At.wt | Atomic ratio | Simplest ratio |
| $N$ | $30.5$ | $14$ | $\frac {30.5}{14}=2.18$ | $\frac {2.18}{2.18}=1$ |
| $O$ | $69.5$ | $16$ | $\frac {69.5}{16}=4.35$ | $\frac {4.34}{2.18}=2$ |
Empirical formula $=$ $NO_2$ and molecular formula $=N_2O_4$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
