MCQ
A compound has an empirical formula ${C_2}{H_4}O$. An independent analysis gave a value of $132.16$ for its molecular mass. What is the correct molecular formula
- A${C_4}{H_4}{O_5}$
- B${C_{10}}{H_{12}}$
- C${C_7}{O_3}$
- ✓${C_6}{H_{12}}{O_3}$
$ = (12 \times 2 + 4 + 16) = 44$
Molecular formula $ = \frac{{{\rm{mol}}{\rm{. wt}}}}{{{\rm{eq}}{\rm{. formula wt}}{\rm{.}}}} \times \, Emp. Formula$
$ = \frac{{132.1}}{{44}} \times {\rm{Emperical \,formula}}$
$ = 3 \times {C_2}{H_4}O = {C_6}{H_{12}}{O_3}$
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