MCQ
A compound has an empirical formula ${C_2}{H_4}O$. An independent analysis gave a value of $132.16$ for its molecular mass. What is the correct molecular formula
  • A
    ${C_4}{H_4}{O_5}$
  • B
    ${C_{10}}{H_{12}}$
  • C
    ${C_7}{O_3}$
  • ${C_6}{H_{12}}{O_3}$

Answer

Correct option: D.
${C_6}{H_{12}}{O_3}$
d
(d)Empirical formula weight ${C_2}{H_4}O$

$ = (12 \times 2 + 4 + 16) = 44$

Molecular formula $ = \frac{{{\rm{mol}}{\rm{. wt}}}}{{{\rm{eq}}{\rm{. formula wt}}{\rm{.}}}} \times \, Emp. Formula$

$ = \frac{{132.1}}{{44}} \times {\rm{Emperical \,formula}}$

$ = 3 \times {C_2}{H_4}O = {C_6}{H_{12}}{O_3}$

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