A condenser having a capacity of $6\,\mu F$ is charged to $100\, V$ and is then joined to an uncharged condenser of $14\,\mu F$ and then removed. The ratio of the charges on $6\,\mu F$ and $14\,\mu F$ and the potential of $6\,\mu F$ will be
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(c) Let ${q_1},\,{q_2}$ be the charges on two condensers
$V = \frac{{{q_1}}}{6} = \frac{{{q_2}}}{{14}}$
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