A parallel plate capacitor of area ' $A$ ' plate separation ' $d$ ' is filled with two dielectrics as shown. What is the capacitance of the arrangement?
Medium
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(c)
$c_1=\frac{(A / 2) \varepsilon_0}{d / 2}=\frac{A \varepsilon_0}{d}, c_2=K \frac{A \varepsilon_0}{d}, c_3=K \frac{A \varepsilon_0}{2 d}$
$\therefore \quad c_{e q .}=\frac{c_1 \times c_2}{c_1+c_2}+c_3=\frac{(3+ K ) K A \varepsilon_0}{2 d( K +1)}$
$\left(\because C_1\right.$ and $C_2$ are in series and resultant of these two in parallel with $C_3$ )
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