A container is divided into two chambers by a partition. The volume of first chamber is $4.5$ litre and second chamber is $5.5$ litre. The first chamber contain $3.0$ moles of gas at pressure $2.0\, atm$ and second chamber contain $4.0$ moles of gas at pressure $3.0\, atm$ .After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is $x \times 10^{-1} atm$. Value of $x$ is.........
JEE MAIN 2021, Diffcult
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