A galvanometer can be converted into an ammeter by connecting
A
Low resistance in series
B
High resistance in parallel
C
Low resistance in parallel
D
High resistance in series
Easy
Download our app for free and get started
C
Low resistance in parallel
c (c)To convert a galvanometer into an ammeter a low value resistance is to be connected in parallel to it called shunt.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A current loop consists of two identical semicircular parts each of radius $R,$ one lying in the $x-y$ plane and the other in $x-z$ plane. If the current in the loop is $i.$ The resultant magnetic field due to the two semicircular parts at their common centre is
If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$. Then the total current I when its figure of merit is $K$ will be
A circular coil of wire carries a current. $PQ$ is a part of a very long wire carrying a current and passing close to the circular coil. If the directions of currents are those shown in figure, what is the direction of force acting on $PQ$ ?
Two coaxial solenoids of different radii carry current $I$ in the same direction. Let $\;{\overrightarrow {\;F} _1}$ be the magnetic force on the inner solenoid due to the outer one and $\;{\overrightarrow {\;F} _2}$ be the magnetic force on the outer solenoid due to the inner one. Then
A galvanometer with its coil resistance $25\,\Omega $ requires a current of $1\,mA$ for its full deflection. In order to construct an ammeter to read up to a current of $2\,A,$ the approximate value of the shunt resistance should be
The ratio of the magnetic field at the centre of a current carrying coil of the radius $a$ and at a distance ‘$a$’ from centre of the coil and perpendicular to the axis of coil is
An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current $'I'$ along the same direction as shown in figure. Magnitude of force per unit length on the middle wire $'B'$ is given by
A circular coil has moment of inertia $0.8 \,kg m ^{2}$ around any diameter and is carrying current to roduce a magnetic moment of $20\, Am ^{2}$. The coil is kept initially in a vertical position and it can rotate freely around a horizontal diameter. When a uniform magnetic field of $4\, T$ is applied along the vertical, it starts rotating around its horizontal diameter. The angular speed the coil acquires after rotating by $60^{\circ}$ will be