A current loop $ABCD$ is held fixed on the plane of the paper as shown in the figure. The arcs $ BC$ (radius $= b$) and $DA $ (radius $= a$) of the loop are joined by two straight wires $AB $ and $CD$. A steady current $I$ is flowing in the loop. Angle made by $AB$ and $CD$ at the origin $O$ is $30^o $. Another straight thin wire with steady current $I_1$ flowing out of the plane of the paper is kept at the origin.
Due to the presence of the current $I_1$ at the origin
AIEEE 2009, Medium
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KEY CONCEPT: $\vec{F}=I(\vec{\ell} \times \vec{B})$
The force on $A D$ and $B C$ due to current $I_{1}$ is zero. This is because the directions of current element $I \overrightarrow{d \ell}$ and magnetic field $\vec{B}$ are parallel.
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