A $100$ $turns$ coil shown in figure carries a current of $2\, amp$ in a magnetic field $B = 0.2\,Wb/{m^2}$. The torque acting on the coil is
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(a) $\tau = NBiA = 100 \times 0.2 \times 2 \times \left( {0.08 \times 0.1} \right) = 0.32\,N \times m$
Direction can be found by Fleming's left hand rule.
Direction can be found by Fleming's left hand rule.
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