A current of $10 \,A$ is maintained in a conductor of cross-section $1 \,cm ^2$. If the number density of free electrons be $9 \times 10^{28} \,m ^{-3}$, the drift velocity of free electrons is .......... $m / s$
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(a)
$i=n e A V_d$
$10=\left(9 \times 10^{28}\right)\left(1.6 \times 10^{-19}\right)\left(10^{-4}\right) V_D$
Solving, we get
$V_D=6.94 \times 10^{-6} \,m / s$
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