A current of $1.5\, {A}$ is flowing through a triangle, of side $9\, {cm}$ each. The magnetic field at the centroid of the triangle is
(Assume that the current is flowing in the clockwise direction.)
JEE MAIN 2021, Diffcult
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${B}=3\left[\frac{\mu_{0} {i}}{4 \pi {r}}\left(\sin 60^{\circ}+\sin 60^{\circ}\right)\right]$
$\tan 60^{\circ}=\frac{\ell / 2}{{r}}$
Where ${r}=\frac{9 \times 10^{-2}}{2 \sqrt{3}} \,{M}$
$\therefore {B}=3 \times 10^{-5}\, {T}$
Current is flowing in clockwise direction so, $\overrightarrow{{B}}$ is inside plane of triangle by right hand rule.
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