A current of $15\,mA$ flows in the circuit as shown in figure. The value of potential difference between the points $A$ and $B$ will be $...\,V$
A$50$
B$75$
C$150$
D$275$
JEE MAIN 2022, Medium
Download our app for free and get started
D$275$
d $i_{1}=\frac{5}{10+5} \times 15 mA =5 mA$
$V _{ A }-5 i -10 i _{1}-10 i = V _{ B }$
$V _{ A }- V _{ B }=75+50+150=275\,V$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
In order to increase the resistance of a given wire of uniform cross section to four times its value, a fraction of its length is stretched uniformly till the full length of the wire becomes $\frac{3}{2}$ times the original length what is the value of this fraction?
In the given circuit the internal resistance of the $18\,V$ cell is negligible. If $R_1 = 400 \,\Omega ,\,R_3 = 100\,\Omega $ and $R_4 = 500\,\Omega $ and the reading of an ideal voltmeter across $R_4$ is $5\,V,$ then the value of $R_2$ will be ........... $\Omega$
The resistivity of iron is$1 \times {10^{ - 7}}\,ohm - m$. The resistance of a iron wire of particular length and thickness is $1\, ohm$. If the length and the diameter of wire both are doubled, then the resistivity in $ohm - m$ will be