$A$ current of $(2.5 \pm 0.05)$ $A$ flows through a wire and develops a potential difference of $(10 \pm 0.1)$ $\mathrm{volt}.$ Resistance of the wire in $\mathrm{ohm},$ is
A$4 \pm 0.12$
B$4 \pm 0.04$
C$4 \pm 0.08$
D$4 \pm 0.02$
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A$4 \pm 0.12$
a $R=\frac{10}{2.5}=4 \pm \Delta R$
$\Delta R=0.03 \times 4=0.12$
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