d
Equivalent thermal resisitance,
$\frac{1}{R} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}$
$\frac{{k\pi {{\left( {2R} \right)}^2}}}{L} = \frac{{{k_1}\pi {R^2}}}{L} + \frac{{{k_2}\pi \left[ {{{\left( {2R} \right)}^2} - {R^2}} \right]}}{L}$
$ \Rightarrow 4k = {k_1} + 3{k_2}$
$ \Rightarrow k = \frac{{{k_1} + 3{k_2}}}{4}$