a
$A_{1} v_{1}=A_{2} v_{2}$
$\pi \mathrm{R}^{2} \mathrm{dh} / \mathrm{dt}=\pi \mathrm{r}^{2} \mathrm{v}$ $...(i)$
$\mathrm{v}=\sqrt{2 \mathrm{gh}}$ $...(ii)$
from equation $(ii)$ put the value of $v$ in equation $( i)$
$-\pi \mathrm{R}^{2} \mathrm{dh} / \mathrm{dt}=\pi \mathrm{r}^{2} \sqrt{2 \mathrm{gh}}$
$\Rightarrow-\int \frac{\mathrm{R}^{2} \mathrm{dh}}{\mathrm{r}^{2} \sqrt{2 \mathrm{gh}}}=\int \mathrm{dt} \Rightarrow-\frac{\mathrm{R}^{2}}{\mathrm{r}^{2} \sqrt{2 \mathrm{g}}} \int_{\mathrm{h}}^{0} \frac{\mathrm{dh}}{\sqrt{\mathrm{h}}}=\int_{0}^{\mathrm{t}} \mathrm{dt}$
on solving $t=46.26$ second