A circular coil of $500$ turns encloses an area of $0.04 \,m^2.$ A uniform magnetic field of induction $0.25\, Wb/m^2$ is applied perpendicular to the plane of the coil. The coil is rotated by $90^o$ in $0.1$ second at a constant angular velocity about one of its diameters. A galvanometer of resistance $25\Omega$ was connected in series with the the coil. The total charge that will pass through the galvanometer is.......$C$
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Induced current
$\mathrm{I}=\frac{\mathrm{E}}{\mathrm{R}} \Rightarrow \frac{\mathrm{dq}}{\mathrm{dt}}=\frac{\mathrm{E}}{\mathrm{R}}=\left(\frac{\mathrm{d} \phi}{\mathrm{dt}}\right) \frac{1}{\mathrm{R}}$
$\Rightarrow \mathrm{q}=\frac{\Delta \phi}{\mathrm{R}}=\frac{\mathrm{NBA}}{\mathrm{R}}$
Total charge $q=\frac{500 \times 0.25 \times 0.04}{25}=0.2 \mathrm{\,C}$
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