A circular coil of diameter $7\,cm$ has $24$ $turns$ of wire carrying current of $ 0.75\,A$. The magnetic moment of the coil is
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(a) $M = NiA = 24 \times 0.75 \times 3.14 \times {(3.5 \times {10^{ - 2}})^2}$
$ = 6.9 \times {10^{ - 2}}\,A{\rm{ - }}\,{m^2}$
$ = 6.9 \times {10^{ - 2}}\,A{\rm{ - }}\,{m^2}$
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