To convert a $800\, mV$ range milli voltmeter of resistance $40 \,\Omega$ into a galvanometer of $100\, mA$ range, the resistance to be connected as shunt is .............. $\Omega $
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$\frac{i}{{{i_g}}} = 1 + \frac{G}{S}$$ \Rightarrow \frac{{i.G}}{{{V_g}}} = 1 + \frac{G}{S} \Rightarrow \frac{{100 \times {{10}^{ - 3}} \times 40}}{{800 \times {{10}^{ - 3}}}} = 1 + \frac{{40}}{S}$
$ \Rightarrow $ $S = 10\,\Omega $.
$ \Rightarrow $ $S = 10\,\Omega $.
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