Two long parallel wires are at a distance of $1$ metre. Both of them carry one ampere of current. The force of attraction per unit length between the two wires is
A$1\,N/m$
B$2 \times {10^{ - 7}}\,N/m$
C$1 \times {10^{ - 2}}\,N/m$
D$4\pi \times {10^{ - 7}}\,N/m$
AIPMT 1998, Medium
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B$2 \times {10^{ - 7}}\,N/m$
b (b) Force per unit length on two parallel current carrying conductor is given by $\frac{F}{l} = {10^{ - 7}} \times 2\frac{{{i_1}{i_2}}}{a}$
$==>$ $\frac{F}{l} = {10^{ - 7}} \times 2 \times \frac{{1 \times 1}}{1} = 2 \times {10^{ - 7}}\,N/m$
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