A circular coil of radius $4\, cm$ and of $20$ $turns$ carries a current of $3$ amperes. It is placed in a magnetic field of intensity of $0.5$ $weber/{m^2}$. The magnetic dipole moment of the coil is.......$ampere - {m^2}$
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(b) $M = NiA = 20 \times \frac{{22}}{7}{(4 \times {10^{ - 2}})^2}3 = 0.3\,A - {m^2}$
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