A circular coil of radius $4\, cm$ and of $20$ $turns$ carries a current of $3$ amperes. It is placed in a magnetic field of intensity of $0.5$ $weber/{m^2}$. The magnetic dipole moment of the coil is.......$ampere - {m^2}$
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A semicircular ring of radius $R$ carrying current $i$ is placed in a magnetic field of intensity $B$ so that plane of wire is perpendicular to magnetic field as shown. Net force acting on the ring is
A proton and an $\alpha -$ particle (with their masses in the ratio of $1 : 4$ and charges in the ratio of $1:2$ are accelerated from rest through a potential difference $V$. If a uniform magnetic field $(B)$ is set up perpendicular to their velocities, the ratio of the radii $r_p : r_{\alpha }$ of the circular paths described by them will be
A charge $Q$ is moving $\overrightarrow{dl}$ distance in the magnetic field $\overrightarrow{ B }$. Find the value of work done by $\overrightarrow{ B }$.
Two long parallel copper wires carry currents of $5\,A$ each in opposite directions. If the wires are separated by a distance of $0.5\,m$, then the force between the two wires is
An imaginary north pole of $10\,Am$ is rotating around an infinite long current carrying wire with $30\,revolution/min.$ on circular path. If current in wire is $5\,A$ then workdone in one second in doing so
Assertion : A proton and an alpha particle having the same kinetic energy are moving in circular paths in a uniform magnetic field. The radii of their circular paths will be equal.
Reason : Any two charged particles having equal kinetic energies and entering a region of uniform magnetic field $\overrightarrow B $ in a direction perpendicular to $\overrightarrow B $, will describe circular trajectories of equal radii.
A galvanometer whose resistance is $120\,\Omega $ gives full scale deflection with a current of $0.05\, A$ so that it can read a maximum current of $10\, A$. A shunt resistance is added in parallel with it. The resistance of the ammeter so formed is .............. $\Omega $
An infinitely long conductor $PQR$ is bent to from a right angle as shown. A current $I$ flows through $PQR$ . The magnetic field due to this current at the point $M$ is $H_1$ . Now, another infinitely long straight conductor $QS$ is connected at $Q$ so that the current in $PQ$ remaining unchanged. The magnetic field at $M$ is now $H_2$ . The ratio $H_1/H_2$ is given by