A circular loop has a radius of $5\, cm$ and it is carrying a current of $0.1\, amp$. Its magnetic moment is
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(d) $M = iA = 0.1 \times \pi \times {\left( {0.05} \right)^2}$
$ = \left( {0.1} \right) \times 3.14 \times 25 \times {10^{ - 4}} = 7.85 \times {10^{ - 4}}\,amp - {m^2}$
$ = \left( {0.1} \right) \times 3.14 \times 25 \times {10^{ - 4}} = 7.85 \times {10^{ - 4}}\,amp - {m^2}$
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