The magnetic field $d\overrightarrow B $ due to a small current element $d\overrightarrow {l\,} $ at a distance $\overrightarrow {r\,} $ and element carrying current $i$ is
AIPMT 1996, Easy
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(d) $ dB = \frac{{{\mu _0}}}{{4\pi }} \cdot \frac{{idl\sin \theta }}{{{r^2}}}$ $==>$ $d\overrightarrow B = \frac{{{\mu _0}}}{{4\pi }} \cdot \frac{{i\,(d\overrightarrow {l\,} \times \overrightarrow {r\,} )}}{{{r^3}}}$
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