A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let $r_{d}$ and $r_{\alpha}$ be their respective radii of circular path. The value of $\frac{r_{d}}{r_{\alpha}}$ is equal to
A$\sqrt{2}$
B$1$
C$2$
D$\frac{1}{\sqrt{2}}$
JEE MAIN 2021, Medium
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A$\sqrt{2}$
a ${I}=\frac{{m} v}{{qB}}=\frac{\sqrt{2 {mk}}}{{qB}}$
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