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6. system of particles and rotational motion — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics6. system of particles and rotational motion1 Mark
MCQ
A fan of moment of inertia $0.6\,kg \times m^2$ is turned upto a working speed of $0.5$ revolutions per second. The angular momentum of the fan is
  • ✓
    $0.6\pi \,kg \times m^2/sec$
  • B
    $6\,kg \times m^2/sec$
  • C
    $3\,kg \times m^2/sec$
  • D
    $\frac{\pi }{6}\,kg \times \,{m^2}/\sec $
✓

Answer

Correct option: A.
$0.6\pi \,kg \times m^2/sec$
a
$L = I\omega  = 0.6 \times 2\pi  \times \frac{1}{2} = 0.6\pi \,kg - {m^2}/\sec $

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