A sounding body of negligible dimension emitting a frequency of $150\,\, Hz$ is dropped from a height. During its fall under gravity it passes near a balloon moving up with a constant velocity of $2m/s$ one second after it started to fall.The difference in the frequency observed by the man in balloon just before and just after crossing the body will be : (Given that -velocity of sound $= 300m/s; g = 10m/s^2$)
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after $1\, sec,$ falling point sound source (with freq $150$ $H z$ ) will attain velocity of $V_{s}=$ $10 m s^{-1},$ and observer sitting on the balloon is coming upward with velocity $V_{o}=$ $2 m s^{-1},$ say frequencies observed

by observer before and after crossing are $n_{1}$ and $n_{2}$ respectively, then

$n_{1}=\frac{300+2}{300-10} 150=156.20 \mathrm{Hz}$

$n_{2}=\frac{300-2}{300+10} 150=144.19 \mathrm{Hz}$

$n_{1}-n_{2}=12 H z(\text {approx})$

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