A fuse wire with radius $1\, mm$ blows at $1.5\, amp$. The radius of the fuse wire of the same material to blow at $3\,A$ will be
Diffcult
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(a) $i \propto {r^{3/2}} \Rightarrow $ $\frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{i_2}}}{{{i_1}}}} \right)^{3/2}} = {\left( {\frac{3}{{1.5}}} \right)^{2/3}} = {(4)^{1/3}}$
$ \Rightarrow {r_2} = {(4)^{1/3}} \times {r_1} = {4^{1/3}}$ ( $r_1 = 1\, mm$)
$ \Rightarrow {r_2} = {(4)^{1/3}} \times {r_1} = {4^{1/3}}$ ( $r_1 = 1\, mm$)
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