A galvanometer has $36\,\Omega $ resistance. If a $4\,\Omega $ shunt is added to this, the fraction of current that passes through the shunt is
  • A$\frac{1}{4}$
  • B$\frac{1}{9}$
  • C$\frac{1}{10}$
  • D$\frac{9}{10}$
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