A gas can be taken from $A$ to $B$ via two different processes $ACB$ and $ADB$. When path $ACB$ is used $60\, J$ of heat flows into the system and $30\, J$ of work is done by the system. If path $ADB$ is used work down by the system is $10\, J$. the heat flow into the system in path $ADB$ is ..... $J$
JEE MAIN 2019, Medium
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As temperature at point $A$ and $C$ is same.
$\therefore$ Internal energy change will be same.
$\mathrm{Q}-\mathrm{W}=\mathrm{Q}^{\prime}-\mathrm{W}^{\prime}$
$60-30=Q^{\prime}-10$
$Q^{\prime}=40 \mathrm{J}$
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