Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from $2 \times {10^{ - 3}}\,{m^3}$ to $3.34{m^3}.$ The work done by the system is about ....... $kJ$
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(d) $W = P\Delta V = 1.01 \times {10^5}(3.34 - 2 \times {10^{ - 3}})$
$ = 337 \times {10^3}J \approx 340\;KJ$
$ = 337 \times {10^3}J \approx 340\;KJ$
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