A hole is made at the bottom of the tank filled with water (density $1000\, kg/m^3$). If the total pressure at the bottom of the tank is $3$ atmosphere ($1$ atmosphere $= 10^5\, N/m^2$), then the velocity of efflux is
AIIMS 2000, Medium
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We know that velocity of efflux, $v = \sqrt {2gh} $
At the bottom of tank pressure is $3$ atmosphere. So, total pressure due to water column
$ = h\rho g = 2 \times {10^5}\,\left( {two\,atmosphere} \right)$
$ \Rightarrow \,gh = \frac{{2 \times {{10}^5}}}{\rho } = \frac{{2 \times {{10}^5}}}{{{{10}^3}}} = 2 \times {10^2}$
$ \Rightarrow v = \sqrt {2 \times 2 \times {{10}^2}} = \sqrt {400} \,m/\sec $
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