A hollow conducting sphere of inner radius $R$ and outer radius $2R$ is given a charge $Q$ as shown in the figure, then the :
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points $A$ and $B$ lie within the same metal hence $V_{A}=V_{B} .$ The potential inside a hollow sphere is same as potential at the surface, hence
$V_{A}=V_{B}=V_{C}=V_{0}$
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