A hydraulic automobile lift is designed to lift vehicles of mass $5000\,kg$. The area of cross section of the cylinder carrying the load is $250\,cm ^2$. The maximum pressure the smaller piston would have to bear is [Assume $g=10\,m / s ^2$]
  • A$200 \times 10^{+6}\,Pa$
  • B$20 \times 10^{+6}\,Pa$
  • C$2 \times 10^{+6}\,Pa$
  • D$2 \times 10^{+5}\,Pa$
JEE MAIN 2023, Easy
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