A liquid drop of diameter D breaks into 27 tiny drops. The change… - Vidyadip

MCQ

A liquid drop of diameter $D$ breaks into $27$ tiny drops. The change in energy is

✓
$2\pi \,TD^2$
B
$4\pi \,TD^2$
C
$\pi \,TD^2$
D
None of these

✓

Answer

Correct option: A.

$2\pi \,TD^2$

a
$\Delta SE = 4\pi R^2T\,\,(n^{1/3}-1)$

$= 4\pi \frac {D^2}{4}T [(27)^{1/3}-1] = 2\pi D^2T$

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