A man holds a spherical shaving mirror of radius of curvature 60cm, and focal length 30cm, at a distance of 15cm, from his nose. Find the position of image, and calculate the magnification.
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Radius of curvature, R = -60cm (concave mirror) f = -30cm, u = -15cm We have$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}=\frac{1}{15}+\frac{1}{-30}$
$\frac{1}{\text{v}}=\frac{1}{30}$
$\text{v}=30\text{cm}$
$\text{m}=-\frac{\text{v}}{\text{u}}$
$\text{m}=-\frac{30}{-15}$
$\text{m}=2$
So, the iamge is formed 30cm behinf the mirrior and the magnification is +2.
$\frac{1}{\text{v}}=\frac{1}{15}+\frac{1}{-30}$
$\frac{1}{\text{v}}=\frac{1}{30}$
$\text{v}=30\text{cm}$
$\text{m}=-\frac{\text{v}}{\text{u}}$
$\text{m}=-\frac{30}{-15}$
$\text{m}=2$
So, the iamge is formed 30cm behinf the mirrior and the magnification is +2.
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