MCQ
A mass m performs oscillations of period $T$ when hanged by spring of force constant $K$. If spring is cut in two parts and arranged in parallel and same mass is oscillated by them, then the new time period will be
  • A
    $2T$
  • B
    $T$
  • C
    $\frac{T}{{\sqrt 2 }}$
  • $\frac{T}{2}$

Answer

Correct option: D.
$\frac{T}{2}$
d
(d) $T \propto \frac{1}{{\sqrt k }}$

==> $\frac{{{T_2}}}{{{T_1}}} = \sqrt {\frac{{{K_1}}}{{{K_2}}}} $$ = \sqrt {\frac{k}{{4k}}} = \frac{1}{2}$

==> ${T_2} = \frac{{{T_1}}}{2}$

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