A mixture of $2\, moles$ of helium gas (atomic mass $= 4\, u$), and $1\, mole$ of argon gas (atomic mass $= 40\, u$) is kept at $300\, K$ in a container. The ratio of their rms speeds $\left[ {\frac{{{V_{rms}}{\rm{(helium)}}}}{{{V_{rms}}{\rm{(argon)}}}}} \right]$, is close to
A$3.16$
B$0.32$
C$0.45$
D$2.24$
JEE MAIN 2019, Medium
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A$3.16$
a $\frac{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{He}}}{\left(\mathrm{V}_{\mathrm{RMS}}\right)_{\mathrm{Ar}}} =\sqrt{\frac{\mathrm{M}_{\mathrm{Ar}}}{\mathrm{M}_{\mathrm{He}}}} $
$=\sqrt{\frac{40}{4}}=\sqrt{10}=3.16$
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