
No. of rounds in a hour $=\frac{3600}{4 \pi}$
(where $4 \pi$ is time for one round) $\approx 287$
Answer is double of $287$ ie $574$
$(a)$ $\left(x^2-v t\right)^2$
$(b)$ $\log \left[\frac{(x+v t)}{x_0}\right]$
$(c)$ $e^{\left\{-\frac{(x+v t)}{x_0}\right\}^2}$
$(d)$ $\frac{1}{x+v t}$

$\left(t_{0}\right.$ represents the instant when the distance between the source and observer is minimum)