A parallel plate capacitor with plates of area $1\,m^2$ each, are at a separation of $0.1\,m.$ If the electric field between the plates is $100\,N/C,$ the magnitude of charge on each plate
JEE MAIN 2019, Medium
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$\mathrm{E}=\frac{\mathrm{q}}{\mathrm{A} \varepsilon_{0}}$
$\Rightarrow \quad \mathrm{q}=\mathrm{E} \mathrm{A} \varepsilon_{0}$
$\Rightarrow \quad \mathrm{q}=100 \times 1 \times 8.85 \times 10^{-12}$
$\Rightarrow \mathrm{q}=8.85 \times 10^{-10}\, \mathrm{C}$
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