A particle executing S.H.M. of amplitude 4 cm and T = 4 ,sec. The time taken by it to move from positive extreme position to

Q: A particle executing $S.H.M.$ of amplitude 4 cm and $T = 4 \,sec.$ The time taken by it to move from positive extreme position to half the amplitude is ..... $\sec$

c (c) Equation of motion $y = a\cos \omega t$ $\frac{a}{2} = a\cos \omega t$ $\Rightarrow \cos \omega t = \frac{1}{2}$ $\Rightarrow \omega t = \frac{\pi }{3}$ $ \Rightarrow \frac{{2\pi t}}{T} = \frac{\pi }{3}$ $\Rightarrow t = \frac{{\frac{\pi }{3} \times T}}{{2\pi }} = \frac{4}{{3 \times 2}} = \frac{2}{3}\sec $

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A particle executing $S.H.M.$ of amplitude 4 cm and $T = 4 \,sec.$ The time taken by it to move from positive extreme position to half the amplitude is ..... $\sec$

A$1$
B$0.33$
C$0.67$
D$1.22$

Medium

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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