MCQ
A particle executing simple harmonic motion of amplitude 5cm has maximum speed 31.4cm/s. the frequency of its oscillations is:
- A1Hz
- B3Hz
- C2Hz
- D4Hz
✓
Answer
- 1Hz
Explanation:
Max speed $\text{v}_{\text{m}}=\text{r}\omega=\text{r}.2\pi\text{v}$
Max speed $\text{v}=\frac{\text{v}_{\text{m}}}{2\pi\text{r}}=\frac{31.4}{2\times3.14\times5}=1\text{Hz}$
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