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Circular Motion — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsCircular Motion3 Marks
Question
A particle is projected with a speed u at an angle $\theta$ with the horizontal. Consider a small part of its path near the highest position and take it approximately to be a circular arc. What is the radius of this circle? This radius is called the radius of curvature of the curve at the point.
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Answer


Particle is projected with speed ‘u’ at an angle $\theta.$ At the highest pt. the vertical component of velocity is‘0’.
So, at that point, velocity $=\text{u}\sin\theta$
centripetal force $=\text{mu}^2\cos^2\Big(\frac{\theta}{\text{r}}\Big)$
At highest pt.
$\text{mg}=\frac{\text{mv}^2}{\text{r}}$
$\Rightarrow\text{r}=\frac{\text{u}^2\cos^2\theta}{\text{g}}$

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