A particle moving in a magnetic field increases its velocity, then its radius of the circle
Easy
Download our app for free and get started
(b) For motion of a charged particle in a magnetic field, we have $r = mv/qB$
i.e. $r\;\alpha \;v$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A moving coil galvanometer has $100$ turns and each turn has an area of $2.0 \mathrm{~cm}^2$. The magnetic field produced by the magnet is $0.01 \mathrm{~T}$ and the deflection in the coil is $0.05$ radian when a current of $10 \mathrm{~mA}$ is passed through it. The torsional constant of the suspension wire is $\mathrm{x} \times 10^{-5} \mathrm{~N}-\mathrm{m} / \mathrm{rad}$. The value of $\mathrm{x}$ is____.
A charged particle with specific charge $S$ moves undeflected through a region of space containing mutually perpendicular uniform electric and magnetic fields $E$ and $B$ . When electric field is switched off, the particle will move in a circular path of radius
In a uniform magnetic field of $0.049 \mathrm{~T}$, a magnetic needle performs $20$ complete oscillations in $5$ seconds as shown. The moment of inertia of the needle is $9.8 \times 10^{-5} \mathrm{~kg} \mathrm{~m}^2$. If the magnitude of magnetic moment of the needle is $x \times 10^{-5} \mathrm{Am}^2$, then the value of ' $x$ ' is :
A uniform magnetic field $B$ is acting from south to north and is of magnitude $1.5$ $Wb/{m^2}$. If a proton having mass $ = 1.7 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C$ moves in this field vertically downwards with energy $5\, MeV$, then the force acting on it will be
The deflection in moving coil galvanometer falls from $25$ divisions to $5$ division when a shunt of $24\ \Omega$ is applied. The resistance of galvanometer coil will be :
A magnetic needle lying parallel to a magnetic field requires $W$ units of work to turn it through $60°$ . The torque required to maintain the needle in this position will be
A proton and an $\alpha -$ particle (with their masses in the ratio of $1 : 4$ and charges in the ratio of $1:2$ are accelerated from rest through a potential difference $V$. If a uniform magnetic field $(B)$ is set up perpendicular to their velocities, the ratio of the radii $r_p : r_{\alpha }$ of the circular paths described by them will be