A particle of charge $q$ and mass $m$ moves in a circular orbit of radius $r$ with angular speed $\omega $. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on
IIT 2000, Medium
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(c)The effective current $i = \frac{{q\omega }}{{2\pi }}$and $A = \pi {r^2}$.
Magnetic moment $M = iA = \frac{1}{2}q\omega {r^2}$
Angular moment $L = I\omega = m{r^2}\omega $ $==>$ $\frac{M}{L} = \frac{q}{{2m}}$
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